4x^2-8y^2=1

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Solution for 4x^2-8y^2=1 equation:


Simplifying
4x2 + -8y2 = 1

Solving
4x2 + -8y2 = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8y2' to each side of the equation.
4x2 + -8y2 + 8y2 = 1 + 8y2

Combine like terms: -8y2 + 8y2 = 0
4x2 + 0 = 1 + 8y2
4x2 = 1 + 8y2

Divide each side by '4'.
x2 = 0.25 + 2y2

Simplifying
x2 = 0.25 + 2y2

Reorder the terms:
-0.25 + x2 + -2y2 = 0.25 + 2y2 + -0.25 + -2y2

Reorder the terms:
-0.25 + x2 + -2y2 = 0.25 + -0.25 + 2y2 + -2y2

Combine like terms: 0.25 + -0.25 = 0.00
-0.25 + x2 + -2y2 = 0.00 + 2y2 + -2y2
-0.25 + x2 + -2y2 = 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-0.25 + x2 + -2y2 = 0

The solution to this equation could not be determined.

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